Hey guys,
I have a .ini file that has 6 categories broke up by ½ marks.
I am trying to figure out if the category called $t if it has anything in it to print this image, if it does not, to not pring that image. Cause in that $t it can only equal t.gif to pring the image. So can somebody please help me make an if statement for that please? Thanks and have a great day!

if ($t eq "t.gif") {
print "<img border=0 src=http://www.desaint.com/desa/images/t.gif>";
if ($t eq "") {
print "No Image";
}
}

this is what I tried but it is not working

I'm not positive I fully understand your question, but the easiest way to do an IF statement of that sort is to first determine if there is anything in the variable $t. (In my code I'm making the assumption that you have the image name in $t) My suggestion is to do the following:

if ($t eq "")
{
print "No image loaded."
}
else
{
print "<img src='http://www.desaint.com/desa/images/$t'>";
}

Of course you can generalize this to make it only work if it has a certain image name, or to do different things for different cases.

Hope this helps.

You need to close your bracket sooner - eg:

Ok well that didnt work,
at the very end of my .ini i have two things $t and $r

you can go to this website and see what I am trying to do

http://12.153.20.72/cgi-bin/remotehome.cgi?product=6
you can go through all the products there is 23 of them,

but I am trying not to print that blank image at the top if that is not there, I am testing this out right above the Product so you see what I am doing but at the end of my code ti has this

½t.gif½½

½t.gif½$r would go here½

and if there is nothing in that $r i want it not even print that image, how do you do that?

nevermind i got it working, thanks alot man