Grep result in a loop and linefeed issue

romainp · 06-13-2008, 09:36 AM

Hi,
I try to grep a file (syslog file) and display the result using a loop. Unfortunatly, there is an issue with the code below because of the libefeed/carriage return.
I try to find a way to have each grep result into a single line so I can use it into a the loop:

Code:

for res in $(grep 'pam_unix' $LOG_DIR/$server--$YEAR-$MONTH_D-$DAY_D_ZERO.log | grep 'session opened' | grep -v 'closed'); do

                echo "res : $res"

done

Right now, each 'res' results is a single word from the grep result... I can't find a way to catch the end of line and put the the line into the 'res' variable.

Any help will be greatly appreciated!
Thanks

Guttorm · 06-13-2008, 10:05 AM

Code:

grep 'pam_unix' $LOG_DIR/$server--$YEAR-$MONTH_D-$DAY_D_ZERO.log | grep 'session opened' | grep -v 'closed' |
while read res ; do 
echo "res : $res"
done

romainp · 06-13-2008, 10:11 AM

Perfect! it works!
thanks for taking the time to help me.