g++ gives compilation error

gagan_bhagat · 01-05-2010, 12:27 AM

in the program given below , while i am trying to compile it gives error.
In function `int main()':
error: `struct GSMRegisterSS_RESULT::GSM_seq11' has not been declared
error: `GSM_seqof202' has not been declared
NOTE :
It is auto generated code for .h file so i cant change any thing in the structure or in the union.

#include<iostream>
using namespace std;

typedef struct GSMRegisterSS_RESULT {
union {

struct GSM_seq11 {

struct GSM_seqof202 {
int code;
}*forwardingFeatureList;

}forwardingInfo;

}u;

}GSMRegisterSS_RESULT;

int main()
{
GSMRegisterSS_RESULT ss;
ss.u.forwardingInfo.forwardingFeatureList=new GSMRegisterSS_RESULT::GSM_seq11::GSM_seqof202;
return 0;
}

smeezekitty · 01-05-2010, 12:36 AM

The error is?

gagan_bhagat · 01-05-2010, 03:56 AM

Hi smeezekitty,

while i am trying to compile it gives error.
In function `int main()':
error: `struct GSMRegisterSS_RESULT::GSM_seq11' has not been declared
error: `GSM_seqof202' has not been declared

ntubski · 01-05-2010, 11:02 AM

The only way I could manage is using templates:

Code:

#include<iostream>
using namespace std;

typedef struct GSMRegisterSS_RESULT {
    union {

        struct GSM_seq11 {

            struct GSM_seqof202 {
                int code;
            }*forwardingFeatureList;

        }forwardingInfo;

    }u;

}GSMRegisterSS_RESULT;

template<typename T>
T* mknew(const T *) {
    return new T();
}

int main()
{
    GSMRegisterSS_RESULT ss;
    ss.u.forwardingInfo.forwardingFeatureList =
        mknew(ss.u.forwardingInfo.forwardingFeatureList);
    return 0;
}

If there is some way to refer to anonymous types, I'd be interested to see it.

johnsfine · 01-05-2010, 12:04 PM

I don't have time to test this myself now, but what about using the gcc extension typeof

Maybe:

ss.u.forwardingInfo.forwardingFeatureList=new typeof(*
ss.u.forwardingInfo.forwardingFeatureList);

gagan_bhagat · 01-05-2010, 11:45 PM

thanks to all of u for the help.