how this implementation for dos.h and conio.h, i cant find gettime() and delay() function in LINUX ?
how its best solution for it?

best regards,
slickenside

add:
how this implementation header from dos.h and conio.h for LINUX ?

There is no such header files as dos.h and conio.h in Linux . You will have to use gettimeofday() defined in sys/time.h and sleep() or nanosleep() defined in unistd.h and time.h respectively. Hope this helps.

CONIO.H is a DOS specific header file, so you are out of luck. For console access, use ncurses.
Do a to learn more.

how many argument can get passing in gettimeofday(). how it can be realize it with hours, minutes, second and milisecond.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
#include <sys/time.h>
#include <sys/unistd.h>




signed int Pangt_rek( int X,int Y);

signed int Pang_ite(int X, int y);



int n;

float t, t1, t2, Rek, Ite;

signed int j, m, d, md, m1, d1, md1; /* global variable */

signed int Pangt_rek( int X,int Y){
delay(10);
if (Y == 0)
return 1.0;
else
return (Pangt_rek(X, Y - 1) * X);
}

signed int Pang_ite(int X, int y){

signed int i;
int Hasil;

if (y != 0) {
delay(10);
Hasil *= X;
}
}

main(int argc,char *argv[]){
printf("2 pangkat n = \t iteratif= \t rekursif= \t");
do {
printf("%d", 6);
gettime(j, m, d, md);
Ite = Pangt_ite(2, n,);
gettime(j, m1, d1, md1);
t1 = m * 600 + d * 100 + md;
t2 = m1 * 600 + d1 * 100 + md1;
t = (t2 - t1) / 100.0;
printf(" : %6.2f", t)
gettime(j, m, d, md);
Rek = Pangt_rek(2, n);
gettimeofday(j, m1, d1, md1);
t1 = m * 600 + d * 100 + md;
t2 = m * 600 + d1 * 100 + md1;
t = (t2 - t1)/100.0;
printf(" : %6.2f\n", t)
} while (n < 130);

n = n + 5;

return EXIT_SUCCESS;

}

how to implement to this code :

gettime(param hours, minute, second, milisecond);

best regards,
slickenside

I could not understand your english.

type :
man gettimeofday to read more about it