char variable is behaving as unsigned char

manohar · 02-14-2011, 11:28 PM

Hi,

i define variable of type char (range -128 to 127). when i tried to print the value after assigning a -ve value to it it displaying a +ve value of that -ve value(256+value).

Tinkster · 02-14-2011, 11:43 PM

Platform, language, compiler, ... ?

Cheers,
Tink

Aquarius_Girl · 02-14-2011, 11:54 PM

Anything like this you are trying to do? This gives me -125 as expected!

Code:

#include <stdio.h>

int main ()
{
     char c;
     
     c = -125;
     printf ("%d\n", c);
     
     return 0;
}

ta0kira · 02-15-2011, 12:19 AM

char doesn't have to be signed by default. What happens when you use signed char?
Kevin Barry