C vs Perl ( about s///g; )

FredrikN · 07-12-2002, 02:22 PM

Hi
I'm a perl prograMmer but I want to try out some C now.

Look at this simple exampel in perl
It will replace all h with H

$tmp = "hello out there";
$tmp = ~s/h/H/g;

output: Hello out tHere

How can I do this in C. I just searched the forum but I can't find anything about this.

Is the problem hard to solve i C ??

Thanks

//FredrikN

dorward · 07-12-2002, 02:44 PM

http://www.ncbi.nlm.nih.gov/IEB/Tool...source/regexp/

pickledbeans · 07-12-2002, 02:49 PM

I guess that sed -e 's/h/H/g' isn't the answer you looking for.... unless you could call sed from with C

Mara · 07-13-2002, 04:23 AM

Code:

#include <stdio.h>
#include <string.h>

int main(){
	int i=0;
	char tmp[]="Hello out there";
	printf("Before: %s\n",tmp);
	for(i=0;i<=strlen(tmp);i++)
		if(tmp[i]=='h') tmp[i]='H';
	printf("After: %s\n",tmp);
	return 0;
}

FredrikN · 07-13-2002, 10:14 AM

Oki, thanks

Works fine