C++: Trouble declaring dynamic array

Hady · 10-31-2005, 04:47 AM

Hi,

Simple question I guess:

Code:

double *array = new double[variableSize];  // WORKS FINE!

now I want to do:

Code:

double *array[3] = new double[variableSize][3];

I get the error:
cannot convert from 'double (*)[3]' to 'double *[3]'

How do I solve this error?

Many thanks in advance for your much appreciated help.

nx5000 · 10-31-2005, 05:28 AM

Quote:

Originally posted by Hady

Code:

double (*array)[3] = new double[variableSize][3];

Hady · 10-31-2005, 05:33 AM

Merci beaucoup!!

dmail · 10-31-2005, 05:53 AM

Code:

double (*array)[3] = new double[variableSize][3];

hmm i didnt know you could do that, i use

Code:

int variableSize, msize;

double **array = new double*[variableSize];
for(int i=0;i<=variableSize-1;i++)array[i] = new double[msize];

thanks for that

nx5000 · 10-31-2005, 06:04 AM

In fact I used the same as dmail

The first is not correctly initialized..

nx5000 · 10-31-2005, 06:10 AM

Quote:

Originally posted by Hady
Merci beaucoup!!

Un tres bon cours en francais:

ftp://ftp2.developpez.be/developps/c/PolyCpp.pdf

nx5000 · 10-31-2005, 06:15 AM

It is correct , I was not sure , I tried

Hady · 11-01-2005, 01:06 AM

merci nx5000 pour le cours C++ en français!

et à bientôt!