Bash scripting with directory checking if exists

netpumber · 11-26-2009, 01:00 PM

Hi!!

I have this code in bash

Quote:

array_log = ([0]="/home" [1]="/usr" [2]="/usr/bin")

for item in ${array_log[*]}
do
if [ -d "${array_log[*]}" ]; then
echo "exists"
fi

done

Somewhere i have an error .. Can you help me ?

i get this one when i m going to run it:

Quote:

./test.sh
./test.sh: line 1: syntax error near unexpected token `('
./test.sh: line 1: `array_log = ([0]="/home")'

Thanks!

18Googol2 · 11-26-2009, 01:14 PM

Well, is array really needed?

Code:

LOG_DIRS="/home /usr /usr/bin"

for dir in $LOG_DIRS; do
        [ -d $dir ] && echo "$dir dir exists" 
done

catkin · 11-26-2009, 01:24 PM

Try removing the spaces either side of the first "=" in array_log = ([0]="/home" [1]="/usr" [2]="/usr/bin")

urban.yoga.journeys · 11-26-2009, 04:48 PM

Quote:

Originally Posted by catkin

Try removing the spaces either side of the first "=" in array_log = ([0]="/home" [1]="/usr" [2]="/usr/bin")

+1

netpumber · 12-01-2009, 04:10 PM

Quote:

echo "Do you want to continue deleting these files (y/n)?"
read answ

if [$answ = "y"]; then
echo ""
echo "Deletitng Files"
for file in $LOG_FILES; do
[ -f $file ] && rm $file && echo "${txtgrn}File Deleted${txtrst}"
done
fi

Why this returns me

line 45: [y: command not found

error?

Something happens in the if clause i think ..:s

tuxdev · 12-01-2009, 04:17 PM

'[' is actually a command and has all the spacing requirements of a command. '[[' is highly preferred if this is supposed to be Bash, not POSIX sh.

chrism01 · 12-01-2009, 07:35 PM

Extending on, [[ ]] also requires spaces around the symbols.