bash - pull out variables from a

elinenbe · 02-15-2008, 12:05 PM

I have a string such as:

PDFJ37455JSJDF| 156|BACON AND EGGS TRANSIT |2005-11-01 02:20:00| 7300|4051 | 0

I would like to put each value into a separate variable (or array) to be used later on.

eg:

Name=PDFJ37455JSJDF
Type=156
Food=BACON AND EGGS TRANSIT
Time=2005-11-01 02:20:00
etc...

I can't figure out a nice way to do this (though I do have some crappy ways). Any help would be appreciated.

Thanks,
Eric

ta0kira · 02-15-2008, 12:39 PM

What about this:

Code:

#!/bin/bash

input="PDFJ37455JSJDF| 156|BACON AND EGGS TRANSIT |2005-11-01 02:20:00| 7300|4051 | 0"

echo "$input" | tr "|" "\n" | while read Name && read Type && read Food && read Time; do
	echo Name: $Name
	echo Type: $Type
	echo Food: $Food
	echo Time: $Time
done

ta0kira

unSpawn · 02-15-2008, 12:57 PM

str='PDFJ37455JSJDF| 156|BACON AND EGGS TRANSIT |2005-11-01 02:20:00| 7300|4051 | 0'
IFS=$'|\t\n'
array=(${str})
]$ echo ${array[2]}
BACON AND EGGS TRANSIT

elinenbe · 02-15-2008, 01:30 PM

Rock on you guys. Both work rather perfectly!

Thanks!

angrybanana · 02-15-2008, 01:35 PM

Quote:

Originally Posted by unSpawn

str='PDFJ37455JSJDF| 156|BACON AND EGGS TRANSIT |2005-11-01 02:20:00| 7300|4051 | 0'
IFS=$'|\t\n'
array=(${str})
]$ echo ${array[2]}
BACON AND EGGS TRANSIT

I was trying something similar to that (using IFS with read) but I couldn't figure out how to get rid of the whitespace in " 156". Does bash have an easy way of doing that?

elinenbe · 02-15-2008, 01:58 PM

I actually have the same problem. Working on something now...

ta0kira · 02-15-2008, 02:36 PM

Add this:

Code:

str="$(echo "$str" | tr " " "\0")"

ta0kira

elinenbe · 02-15-2008, 02:41 PM

or this:

Code:

# remove leading white spaces
str=${str## }
# remove trailing white spaces
str=${str%% }

radoulov · 02-15-2008, 05:44 PM

With zsh:

Code:

$ s="PDFJ37455JSJDF| 156|BACON AND EGGS TRANSIT |2005-11-01 02:20:00| 7300|4051 | 0"
$ a=(${${${(s:|:)s}# }% })                                                          
$ print -$a[2]-
-156-

ghostdog74 · 02-15-2008, 07:47 PM

Quote:

Originally Posted by angrybanana

I was trying something similar to that (using IFS with read) but I couldn't figure out how to get rid of the whitespace in " 156". Does bash have an easy way of doing that?

how about this

Code:

# IFS="|"
# echo ${str}
PDFJ37455JSJDF  156 BACON AND EGGS TRANSIT  2005-11-01 02:20:00  7300 4051   0
# IFS="| "
# echo ${str}
PDFJ37455JSJDF 156 BACON AND EGGS TRANSIT 2005-11-01 02:20:00 7300 4051 0

angrybanana · 02-15-2008, 08:40 PM

Quote:

Originally Posted by ghostdog74

how about this

Code:

# IFS="|"
# echo ${str}
PDFJ37455JSJDF  156 BACON AND EGGS TRANSIT  2005-11-01 02:20:00  7300 4051   0
# IFS="| "
# echo ${str}
PDFJ37455JSJDF 156 BACON AND EGGS TRANSIT 2005-11-01 02:20:00 7300 4051 0

That splits "BACON AND EGGS" into separate fields. Guess string substitution is the best way to do it.

ghostdog74 · 02-15-2008, 11:36 PM

Quote:

Originally Posted by angrybanana

That splits "BACON AND EGGS" into separate fields. Guess string substitution is the best way to do it.

ah.yes.my bad for missing that one.

Code:

# set -- $str
# echo $3
BACON AND EGGS TRANSIT