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What does putting ${ } around statements in shell do? Sometimes I see it done with legitimate variables, and other times with expressions. What's the deal? Thanks
it makes quoting variables easier, for example you can't do "echo thisisthenumber$itest" where $i is a variable, but "echo thisisstillthe${i}test" will substitute just fine. it's also used when you're doing regular expression substitutions directly in bash, i'd give you an example but i can never find them online, as mos people just use grep or awk instead. so basially evaluates the expression in the curly brackets in terms of bash variables and other bash functions.
(list) list is executed in a subshell environment (see COMMAND EXECUTION ENVIRONMENT
below). Variable assignments and builtin commands that affect the shell’s envi-
ronment do not remain in effect after the command completes. The return status
is the exit status of list.
{ list; }
list is simply executed in the current shell environment. list must be termi-
nated with a newline or semicolon. This is known as a group command. The return
status is the exit status of list. Note that unlike the metacharacters ( and ),
{ and } are reserved words and must occur where a reserved word is permitted to
be recognized. Since they do not cause a word break, they must be separated from
list by whitespace.
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