same find command not working in bash script, quotes?

QuakerOatz · 07-14-2003, 11:54 AM

I use the following command to shrink photos in a particular directory. The command works perfectly from the bash shell command line.

Code:

find . -iname '*.jpg' -exec convert {} -resize 50%x50% -quality 75 {} \;

... but once I throw this line a bash script, I get

Quote:

find: missing argument to `-exec'

I've written a few hundred bash scripts and have never encountered this problem. find seems to be extremely picky in its notation and has a few "quirks" that I haven't encountered with any other command.

Thanks for the help!

QuakerOatz · 07-14-2003, 12:04 PM

Errr.. I figuired this out about 10 seconds after posting. Besides wasting disk space, perhaps this may be of some to others... for some reason I needed to escape the { and } when using the find command in the shell script... wierd. So this is what worked:

Code:

find . -iname '*.jpg' -exec convert \{\} -resize 50%x50% -quality 75 \{\} \;