[SOLVED] Help with find/replace in vi

Mr. Swillis · 02-08-2010, 01:29 PM

Hello,

I'm in the middle of a data migration project and I have a text file where the data in one of the fields contains a "\" at the end of each line. I know how to do a find and replace on ALL backslashes using something like this:

Code:

:%s/\\//g

The above example would replace all backslashes with nothing, effectively "removing" them. Does anyone know how I can apply a similar function that only removes the backslashes that exist at the end of a line?

Thanks!

Swill

rweaver · 02-08-2010, 01:33 PM

add $ which means "at the end of the line"

edit: ^ means beginning of the line conversely. A command I use frequently when viewing config files for example is 'grep -v "^#" filename' which basically says show me the file minus any line that starts with a # sign.

druuna · 02-08-2010, 01:34 PM

Hi,

:%s/\\$//

Hope this helps.

Mr. Swillis · 02-08-2010, 01:57 PM

Excellent, thanks for the quick replies. I figured the "$" would be involved, but I wasn't sure where to put it in the command. This totally did the trick for me.

Thanks again!

Swill