[SOLVED] conf file parser for bash?

Basher52 · 08-12-2020, 09:59 AM

Hi!

Anyone in here knows a nice conf file parser for bash?
It's supposed to look like yum.conf, sections, names and it's values.
It's a bash script that's gonna read it and use its values for when it's running.

Instead of creating my own there must be plenty of these already made but I just can't find any.

//B52

UPDATE: Also if there is a conf file writer would be superb so I can write to it too

shruggy · 08-12-2020, 10:24 AM

See this post.

pan64 · 08-12-2020, 10:28 AM

if you mean the usual ini file format
here is a simple one: https://gist.github.com/splaspood/1473761 or here is a modified version with writer: https://ajdiaz.wordpress.com/2008/02...sh-ini-parser/
and here is the "most advanced" one: https://github.com/albfan/bash-ini-parser (as far as I know)

ondoho · 08-12-2020, 01:53 PM

From a discussion in another forum:

Code:

# Usage: parse_config_vars <file>
# Preexisting variables will be overwritten.
parse_config_vars(){
    local line key value entry_regex
    entry_regex_quotes="^[[:blank:]]*([[:alpha:]_][[:alnum:]_]*)[[:blank:]]*=[[:blank:]]*('[^']+'|\"[^\"]+\")[[:blank:]]*(#.*)*$"
    entry_regex_loose="^[[:blank:]]*([[:alpha:]_][[:alnum:]_]*)[[:blank:]]*=[[:blank:]]*([^#]*[^#[:blank:]])*"
    while read -r line
    do
        [[ -n $line ]] || continue
        if [[ $line =~ $entry_regex_quotes ]]
        then
            value=${BASH_REMATCH[2]#[\'\"]} # strip quotes
            value=${value%[\'\"]}
        elif [[ $line =~ $entry_regex_loose ]]
        then
            value=${BASH_REMATCH[2]}
        else
            continue
        fi
        key=${BASH_REMATCH[1]}
        echo "Parsing config (new regex): ${key} = ${value}"
        declare -g "${key}"="${value}"
    done < "$1"
    return 0
}

It assigns config variables' values to bash variables of the same name IIRC, without the dangers of sourcing.

Basher52 · 08-13-2020, 01:02 PM

I'm gonna check all these.
Thanks all