Hi all,
I have a very basic question to ask...
do not mind
How do you figure out if a command is a "built in"(in any shell) or not?

PSlease dont flame me!!!

"man bash" gives you all the built-ins.

OR

Look for the command in /bin or /sbin. If it's not there, its a built-in

the type command. binaries need to be in users path.
as in:
type bash
type type
type !

It also tells you if a command is hashed or an alias.

I tried,
type awk
awk is /usr/bin/awk
however a man awk,
gives me its presence even in /usr/xpg4/bin/awk
Similarly there are many commands that are present in 2 or more dirs..
why is it?
Is it dependent on type of operation that is specified on that command?
eg,
Assuming that ls is in /usr/bin and /usr/xpg4/bin
is it that,
when i do ls -l it reads from /usr/bin/
and ls -a reads it from /usr/xpg4/bin

type ls
ls is hashed (/usr/bin/ls)
What does hashed mean?
Also the same was the result when i did a "type touch"
Could i know what these mean?

Thanks

Usually to comply with differing standards.
No. The command that will be executed is the first one found in your PATH.
It means the shell has recorded the command location to speed up further execution.

Run the "hash" command to see which commands are remembered.

Are you on openSolaris or something?