bash script to test string complexity (like password complexity)

robertjinx · 05-12-2010, 08:22 AM

Hi guys, I'm looking for a script which is testing how complex an "added" string is, for example like the user is changing his password and check how complex it is, if it included letters (lower/upper case), numbers and other characters.

Im doing this for password check, the user type's the password and must be 6 characters long, have upper case letters lets say and numbers and so on.

If anyone knows where I could find some bash script which is doing this, it would be really cool.

Thanks!

catkin · 05-12-2010, 09:37 AM

Here's proof of concept

Code:

#!/bin/bash

readonly re_digit='[[:digit:]]'
readonly re_lower='[[:lower:]]'
readonly re_punct='[[:punct:]]'
readonly re_space='[[:space:]]'
readonly re_upper='[[:upper:]]'

score=0
for re in "$re_digit" "$re_lower" "$re_punct" "$re_space" "$re_upper"
do
    [[ $1 =~ $re ]] && let score++
done

echo "Score is $score"

Note: character class "[:punct:]" includes all the printable ASCII characters not included in the others -- ~ ! @ # $ % ^ & * ( ) _ + ` - = { } | [ ] \ : " ; < > ? , . /

robertjinx · 05-12-2010, 02:58 PM

This is quite cool... thx!