[SOLVED] Umask -> Bash.bashrc file ?

jv2112 · 12-23-2010, 07:21 AM

I have set my umask parameter below in my /etc/bash.bashrc file but the value comes up as 0022.

Code:

umask=0027

What am I doing wrong ? Or what am I not understanding ?

My end goal is to ensure that all files can't be deleted/edited by anyone but the owner/root and the users within the group can read them. Is this the correct value ?

Thank You in advance for your time.

Guttorm · 12-23-2010, 08:11 AM

Hi

The number seems right, but you should use umask without the =. Try this instead:

Code:

umask 0027

crts · 12-23-2010, 08:23 AM

Hi,

all your code does is assign the value '0027' to a variable named 'umask'. To actually change the umask value you will have to issue

Code:

umask 0027

at some point. Or, if you want to use the variable then it should be

Code:

umask $umask

Possible error sources are that your script might not issue the actual umask command or it is not being sourced at all. Please post your complete /etc/bash.bashrc and your ~/.bashrc file. Chances are that the value is overwritten at some point. Also note, that if bash is called with 'sh' it default to --norc option:

Code:

--norc        Do not read and execute  the  system  wide  initialization  file
              /etc/bash.bashrc  and the personal initialization file ~/.bashrc
              if the shell is interactive.  This option is on  by  default  if
              the shell is invoked as sh.

jv2112 · 12-23-2010, 02:42 PM

Thanks for the replies.

My Syntax was off. I changed to umask 0027 (less = ) and it I was all set.

Happy Holidays !!!