Seeking help with date calculations in bash (on MacOS-X)

Pap · 09-26-2013, 09:20 AM

Quote:

Originally Posted by sparky90ful

it gives me this

Code:

01-r3p05:ex_4 florea_g$ ./incercare.sh 15-May-1990
Elapsed time: date: illegal option -- -
usage: date [-jnu] [-d dst] [-r seconds] [-t west] [-v[+|-]val[ymwdHMS]] ... 
            [-f fmt date | [[[mm]dd]HH]MM[[cc]yy][.ss]] [+format]
43 years, 9 months, 9 days, 14 hours, 10 minutes, 50 seconds.
301-r3p05:ex_4 florea_g$

Are you sure you followed the steps I mentioned? I just tried your example and I get:

Code:

./time_elapsed 15-May-1990
Elapsed time: 23 years, 4 months, 20 days, 17 hours, 18 minutes, 24 seconds.

Note: spacing does matter in scripts; not everywhere, but it does matter in many cases.
By the way, you don't have to add the suffix ".sh", if the script has the "executable" flag set.

Firerat · 09-26-2013, 09:23 AM

Quote:

Originally Posted by Pap

Are you sure you followed the steps I mentioned? I just tried your example and I get:

Code:

./time_elapsed 15-May-1990
Elapsed time: 23 years, 4 months, 20 days, 17 hours, 18 minutes, 24 seconds.

By the way, you don't have to add the suffix ".sh", if the script has the "executable" flag set.

you don't 'have' to add .sh at all

personally I do, so I immediately know it is a script and not a binary

colucix · 09-26-2013, 10:25 AM

Quote:

Originally Posted by sparky90ful

it gives me this

Code:

01-r3p05:ex_4 florea_g$ ./incercare.sh 15-May-1990
Elapsed time: date: illegal option -- -
usage: date [-jnu] [-d dst] [-r seconds] [-t west] [-v[+|-]val[ymwdHMS]] ... 
            [-f fmt date | [[[mm]dd]HH]MM[[cc]yy][.ss]] [+format]

At this point it's clear that you're running your scripts on MacOS-X and the date command is quite different from the GNU date. Therefore, any suggestion to use date -d or date --date is not applicable. My advice is to stick with bash and do all the necessary calculations using "day" as units and taking into account leap years.

Habitual · 09-26-2013, 10:25 AM

Pap:
2 methods work here:

Code:

elapsed_time 06/05/1960
53 years, 4 months, 6 days, 11 hours, 20 minutes, 21 seconds.
elapsed_time 5-Jun-1960
53 years, 4 months, 6 days, 11 hours, 22 minutes, 42 seconds.

Good stuff, Maynard.

Pap · 09-26-2013, 10:32 AM

Quote:

Originally Posted by Habitual

Pap:
2 methods work here:

Code:

elapsed_time 06/05/1960
53 years, 4 months, 6 days, 11 hours, 20 minutes, 21 seconds.
elapsed_time 5-Jun-1960
53 years, 4 months, 6 days, 11 hours, 22 minutes, 42 seconds.

Good stuff, Maynard.

We didn't know you were trying to do all that on a Mac. Apparently, the date command is not the same on MacOS-X, as colucix already mentioned. Glad it worked in the end.

Habitual · 09-26-2013, 11:16 AM

Quote:

Originally Posted by Pap

We didn't know you were trying to do all that on a Mac. Apparently, the date command is not the same on MacOS-X, as colucix already mentioned. Glad it worked in the end.

Yeah, I just now read the "Mac" subject line.
Has it been there all along, or was it changed?
I thought the subject was "Seeking help" yesterday?

I tend to power through stuff sometimes.
I really should drink de-caf.

colucix · 09-26-2013, 11:22 AM

Quote:

Originally Posted by Habitual

I thought the subject was "Seeking help" yesterday?

The subject was "Please Help Me", something we tend to avoid, therefore I've changed it to something more meaningful.

sparky90ful · 09-26-2013, 11:54 AM

someone could help me with days?

Code:

string=$1
IFS=-
set $string
year=$3
mounth=$2
day=$1

an=`date +%Y`
luna=`date +%m`
zi=`date +%d`

difan=$(($an-$year))

if [[ $luna < $mounth && $zi < $day ]]
	then 
	difan2=$(($difan-1))
else 
	difan2=$difan
fi

if [[ $difan2 > 1 ]]
	then
	echo "Age : $difan2 ans"
     else 
    echo "Age : $difan2 an"
    fi 

z1=`date -jf "%d-%m-%Y" $day-$mounth-$year "+%s"`
z2=`date -jf "%d-%m-%Y" $zi-$luna-$an "+%s"`
z3=$(($z1-$z2))
zile=$(($z3/86400))

if [[ $zile < 0 ]]
	then 
	zilecorecte=$(($zile+365))
else
	zilecorecte=$zile
fi

if [[ $zilecorecte > 1 ]]
   then
   echo "Prochain anniversaire dans : $zilecorecte jours"
   else 
   echo  "Prochain anniversaire dans : $zilecorecte jour"
fi

i cant obtain the days which it rest till his next birthday can somone help me?

Firerat · 09-26-2013, 02:13 PM

well you have the right syntax for your date command now

But, you still have me out by 1 year

28-09-2000 should be 12, your script gets 13

For now.. lets not worry about that

So, you have todays date as seconds from epoch.. (1970-01-01 UTC)
and you have the birthdate, again in seconds BUT for this year!
good

(This years birthday in seconds ) - ( today in seconds ) = seconds until birthday
Now, if that is negative, go back and do again but add a year

then it is just a question of converting seconds to days, weeks, hours, mins even seconds!.
I wouldn't bother with months, since it just complicates things

Firerat · 09-27-2013, 01:26 AM

I figured Mac OSX is basically BSD
so explored date in BSD it dosn't work quite as I expected
I certainly prefer the Linux Version

Anyway, to get the same result as

Code:

date +%s --date="2013-01-01"

I used this

Code:

date -j -f "%Y-%m-%d_%H%M%S" "2013-01-01_000000" "+%s"

The rest is just number crunching
and a few tricks for 'presentation'

sparky90ful · 09-27-2013, 03:29 AM

Finaly i think is ready can someone test it please?

Code:

string=$1
IFS=-
set $string
year=$3
mounth=$2
day=$1

an=`date +%Y`
luna=`date +%m`
zi=`date +%d`

difan=$(( $an-$year ))

if [[ "$luna" < "$mounth" || "$zi" < "$day" ]]
	then 
	difan2=$(( $difan-1 ))
else 
	difan2=$difan
fi

if [[ $an = $year && $luna < $mounth ]]
	then 
	difan2=0
fi

if [[ $difan2 > 1 ]]
	then
	echo "Age : $difan2 ans"
     else 
    echo "Age : $difan2 an"
    fi 

z1=`date -jf "%d-%m" $day-$mounth "+%s"`
z2=`date -jf "%d-%m" $zi-$luna "+%s"`
z3=$(($z2-$z1))
zile=$(( $z3/86400 ))

if [[ $zile=-* ]]
	then 
	zileb=$(($zile+365))
fi


if [[ $zile > 1 ]]
   then
   echo "Prochain anniversaire dans : $zileb jours"
   else 
   echo  "Prochain anniversaire dans : $zileb jour"
fi

Firerat · 09-27-2013, 03:53 AM

yeah seems to be working

tested on both Debian and FreeBSD9.2

so now you need to do the days until next birthday

just a note on "code style",
I see you are using tabs

I used to use tabs, but did some things in Android and they used a 4 space indent
using spaces may seem more effort, but as you can see in your code box, it often translates to be equivalent to 8 spaces, and can make things 'awkward'

some good notes on it here.
http://wiki.bash-hackers.org/scripting/style

sparky90ful · 09-27-2013, 04:04 AM

Quote:

Originally Posted by Firerat

yeah seems to be working

tested on both Debian and FreeBSD9.2

so now you need to do the days until next birthday

just a note on "code style",
I see you are using tabs

I used to use tabs, but did some things in Android and they used a 4 space indent
using spaces may seem more effort, but as you can see in your code box, it often translates to be equivalent to 8 spaces, and can make things 'awkward'

some good notes on it here.
http://wiki.bash-hackers.org/scripting/style

the days is made to
now should be working well

ps: code style i started coding since 4 days so.........i am big noob

i still have a problem:
-if i put 28-06-1994 he gives me the correct result 19 years 274 days
-but if his birthday is tommorow so 28-09-1994 he gives me the good days but the age must be 18 and he gives me 19 can anyone help me?
ps2: SOLVED

Code:

string=$1
IFS=-
set $string
year=$3
mounth=$2
day=$1

an=`date +%Y`
luna=`date +%m`
zi=`date +%d`

difan=$(( $an-$year ))

if [ "$luna" -le "$mounth" ] && [ "$zi" -lt "$day" ] || [ "$luna" -lt "$mounth" ]
	then 
	difan2=$(( $difan-1 ))
else 
	difan2=$difan
fi

if [[ $an = $year && $luna < $mounth ]]
	then 
	difan2=0
fi

if [[ $difan2 > 1 ]]
	then
	echo "Age : $difan2 ans"
     else 
    echo "Age : $difan2 an"
    fi 

z1=`date -jf "%d-%m" $day-$mounth "+%s"`
z2=`date -jf "%d-%m" $zi-$luna "+%s"`
z3=$(($z1-$z2))
zile=$(( $z3/86400 ))

if [[ $zile < 0 ]]
	then 
	zileb=$(($zile+365))
else
	zileb=$zile

fi


if [[ $zile > 1 ]]
   then
   echo "Prochain anniversaire dans : $zileb jours"
   else
   echo  "Prochain anniversaire dans : $zileb jour"
fi

Firerat · 09-27-2013, 05:12 AM

bet you are fed up with scripting now

OK, so here is how I did it ( see below )
Don't panic, I have been doing this a while

besides, probably has some bugs it it

I don't think it is 100% accurate, but close enough

obviously if after 4 days you submit that, questions will be asked
but maybe you can pull some bits from it
I've included some links for you to read

best if you read it in something with syntax highlighting

Code:

#!/usr/bin/env bash


# I don't know about macOSX , but the shabang above works with both Linux and FreeBSD
# however, some Linux distos may have env in a different PATH, which is a real pain

# NOTE: this script has no error checking !!!
# 

string=$1
OrigIFS=$IFS
IFS=-
set $string
y=$3
m=$2
d=$1
IFS=$OrigIFS

# Figured the below was a nice easy test to figure out which date syntax to use
# http://www.tldp.org/LDP/abs/html/io-redirection.html
# note the redirection to /dev/null
# to stop pesky messages on screen ;)

date --date="$(date +%Y)" 2> /dev/null 1> /dev/null && OS=Linux || OS=BSD-MacOSX

#########
# The above is equivalent to this:
#
# if [[ $($date --date="$(date +%Y)" 2> /dev/null 1> /dev/null && OS=Linux || OS=BSD-MacOSX) ]]
# then
#     OS=Linux
# else
#     OS=BSD-MacOSX
# fi
########## http://www.tldp.org/LDP/abs/html/ops.html#ANDOR



# below is a function
# http://www.tldp.org/LDP/abs/html/functions.html
# I use three of them in this script
#

GetAge () {

case $OS in
         Linux) SecondsSince=$(( $( date +%s ) - $( date +%s --date="${y}-${m}-${d}" ) ));;
    BSD-MacOSX) SecondsSince=$(( $( date +%s ) - $( date -j -f "%Y-%m-%d_%H%M%S" "${y}-${m}-${d}_000000" "+%s" ) ));;
esac
# case http://www.tldp.org/LDP/abs/html/testbranch.html#EX29
# equivalent :
# 
# if [[ "$OS" == "Linux" ]]
# then
#    SecondsSince=$(( ...
# elif [[ "$OS" == "BSD-MacOSX" ]]
# then
#    SecondsSince=$(( ...
# 
#### 
HoursSince=$(( $SecondsSince / 3600 ))
Days=$(( $HoursSince / 24 ))
Years=$( awk '{print $1/365.242199}' <<< $Days )
# Not perfect.
# 365.242199 from 
# http://www.timeanddate.com/date/leapyear.html
# 
Remainder="0.${Years/*.}"
# above and below see http://www.tldp.org/LDP/abs/html/refcards.html#AEN22664
Years="${Years%.*}"
RemainderDays=$( awk '{printf "%d",365.242199*$1}' <<< $Remainder )
ThisYear=$(date +%Y)
printf "%21s" "Age : "
printf "$(s_suffix $Years year) $(s_suffix $RemainderDays day)\n"
########## ^ called the s_suffix function, ( bottom of script )
# gave it the Age ( actually, I should rename Years to AgeInYears ;) )
# and year ( as a string ) 

case $(( ${Years} + 1 )) in
  1|*[2-9][1]) suffix="st";;
  2|*[2-9][2]) suffix="nd";;
  3|*[2-9][3]) suffix="rd";;
            *) suffix="th";;
esac
# case again, with Regular expresion


while true;do
  printf "%21s" "$(( ${Years} + 1 ))${suffix} Birthday in : "
  CountDown
# ^ the below function
  printf "%-10s" ""
# ^^ comment that out to see why it is there ;)
  printf "\r"
  sleep 1
done
}
# I shall let you look up while loops ;)

CountDown () {
case $OS in
         Linux) SecondsToGo=$(( $( date +%s --date="${ThisYear}-${m}-${d}" ) - $( date +%s ) ));;
    BSD-MacOSX) SecondsToGo=$(( $( date -j -f "%Y-%m-%d_%H%M%S" "${ThisYear}-${m}-${d}_000000" "+%s" ) - $( date +%s ) ));;
esac
(( $SecondsToGo < 0 )) && \
case $OS in
         Linux) SecondsToGo=$(( $( date +%s --date="$((${ThisYear}+1))-${m}-${d}" ) - $( date +%s ) ));;
    BSD-MacOSX) SecondsToGo=$(( $( date -j -f "%Y-%m-%d_%H%M%S" "$((${ThisYear}+1))-${m}-${d}_000000" "+%s" ) - $( date +%s ) ));;
esac

# take advantage of the 'rounding', go back and find the difference ;)
# 
HoursToGo=$(( $SecondsToGo / 3600 ))
SecondsToGo=$(( $SecondsToGo - $(( $HoursToGo * 3600 )) ))

DaysToGo=$(( $HoursToGo / 24 ))
HoursToGo=$(( $HoursToGo - $(( $DaysToGo * 24 )) ))

WeeksToGo=$(( $DaysToGo / 7 ))
DaysToGo=$(( $DaysToGo - $(( $WeeksToGo * 7 )) ))

MinsToGo=$(( $SecondsToGo / 60 ))
SecondsToGo=$(( $SecondsToGo - $(( $MinsToGo * 60 )) ))

for Output in "$WeeksToGo week" "$DaysToGo day" "$HoursToGo hour" "$MinsToGo minute" "$SecondsToGo second";do
   s_suffix $Output
done
# another loop to look at
# 
}
s_suffix (){
# expects a number and a string
# if greater than 1 add an s to the end of the 'string'
# so week becomes weeks, day days and so on
# add if 0, print nothing
case $1 in
   0) ;;
   1) printf "${1} ${2} ";;
   *) printf "${1} ${2}s ";;
esac
}
GetAge

# was fun :)

sparky90ful · 09-27-2013, 05:20 AM

Maybe for you was fun but for me ...........yes i have a satisfaction so.......that's god but like i say i am coding since 4 days i didn't knew anything so now i strt with sell which is sooooooow hard to understand anyway for me is hard so thanks at all for your replays and i hope you will help me in future because now i have a project to make a data base with some functions so i didn't know from where to start.........but if someone have some hints plese tell me.