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Old 01-23-2014, 03:30 PM   #1
tlegend33
LQ Newbie
 
Registered: Sep 2013
Posts: 20

Rep: Reputation: Disabled
sed multiple lines use in if statement


I have a utility that produces a report which includes the below section:

Code:
 recommended_actions
---------------------
(0 rows)
I want to set a variable for this section:

Code:
ALERT=`sed -e '/recommended_actions/,/(0 rows)/!d' ${LOGFILE}`

echo $ALERT
recommended_actions --------------------- (0 rows)
I then want to send an email if $ALERT equals something else, ie:
Code:
 recommended_actions
---------------------
Replace Disk!
(1 row)
Code:
if [[ ${ALERT} != "recommended_actions --------------------- (0 rows)" ]] ; then
         mail -s "ALERT: ${HOSTNAME} disk monitor" ${DBA} < ${LOGFILE}
fi
With this set up, I receive an email regardless of what $ALERT equals. How can I set this to only send me an email if there's something beneath the "recommended actions" line?

Thanks.
 
Old 01-23-2014, 08:08 PM   #2
grail
LQ Guru
 
Registered: Sep 2009
Location: Perth
Distribution: Manjaro
Posts: 9,485

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Try placing set -xv at the top of your script after the initial interpreter line and see what ALERT is being set to and why the test is failing.
 
  


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