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Old 05-15-2012, 06:13 AM   #1
vanish78
LQ Newbie
 
Registered: May 2011
Posts: 13

Rep: Reputation: 9
Run shell script on multiple linux servers


Hi There,
RHEL

I want a script that will check disk space on multiple servers. I can do a df -h with :

PHP Code:
for i in server1 server2 server3
do
ssh $i df -h
done 
But I want to run this script (which this forum helped me with!)

PHP Code:
#!/bin/sh
for i in msrac01
do
ssh $i df=`df -Pl | grep "^/dev" | awk '{print $5, $6}' | sed "s/%//"`
echo 
"$df| while read percent fs
do
    if [ 
$percent -gt 90 ] ; then
       
echo "$percent"
    
fi
done 
Please help.
 
Old 05-15-2012, 06:32 AM   #2
pan64
LQ Addict
 
Registered: Mar 2012
Location: Hungary
Distribution: debian/ubuntu/suse ...
Posts: 21,850

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I remember I saw this script, and I also remember I gave you a one liner instead of this terrible code.
So I suggest you to use a much simple script and you will be able to use that with ssh:

http://www.linuxquestions.org/questi...9/#post4659230

Code:
cmd="this is a one line long script"
for i in server1 server2 server3 
do
ssh $i $cmd
done
and also you may need take care of ' and " and ` signs.
 
1 members found this post helpful.
Old 05-15-2012, 07:09 AM   #3
colucix
LQ Guru
 
Registered: Sep 2003
Location: Bologna
Distribution: CentOS 6.5 OpenSuSE 12.3
Posts: 10,509

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I agree with pan64. Using a simple command is far simpler. In addition, to avoid the quotes headache you might run the df command remotely and parse it locally, e.g.
Code:
#!/bin/sh
for i in something
do
  df=`ssh $i "df -Pl"`
  echo "$df" | awk '/^\/dev/{sub(/%/,"",$5); if ($5 > 90) print $5, $6}'
done
adding something to identify the server from which you get some result.

Moreover, notice that usually you don't need to run grep, awk and sed together, since awk can do it all!
 
1 members found this post helpful.
Old 05-16-2012, 09:39 AM   #4
vanish78
LQ Newbie
 
Registered: May 2011
Posts: 13

Original Poster
Rep: Reputation: 9
Hi,

Ok I used the "lighter script" :

PHP Code:
#!/bin/sh
for i in server1
do
  
df=`ssh $i "df -Pl"`
  echo 
"$dfawk '/^\/dev/{sub(/%/,"",$5); if ($5 > 95) print $5}'
done 
But not getting any results, but it works on server2. What can be the reason?
 
Old 05-16-2012, 09:48 AM   #5
colucix
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Registered: Sep 2003
Location: Bologna
Distribution: CentOS 6.5 OpenSuSE 12.3
Posts: 10,509

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No filesystem with usage > 95%? What is the difference between the two servers in terms of OS, shell, awk version and so on?
 
Old 05-16-2012, 10:42 AM   #6
pan64
LQ Addict
 
Registered: Mar 2012
Location: Hungary
Distribution: debian/ubuntu/suse ...
Posts: 21,850

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I would simplify it:
Code:
for i in <server list>
do
  echo server: $i  # if you want to print it just do it
  ssh $i df -Pl | awk ' here is the script '
done
you can also try awk -v server="$i" ' script ' if you want to handle the server name inside the awk script.
 
1 members found this post helpful.
  


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