[SOLVED] Remove extension and specified number of characters from a file name

GPGAgent · 11-07-2022, 12:59 PM

I have a file name 0001_ThisBook.mp3 and I want to extract just the name ThisBook and I've come up with this using basename, but is there a better way

Code:

 X="0001_ThisBook.mp3"
echo "$(basename ${X:5:99} .mp3)"

boughtonp · 11-07-2022, 01:09 PM

There's no need for the :99 part, and equivalent to basename can be achieved in Bash itself.

See BashFAQ #73: How can I use parameter expansion? How can I get substrings? How can I get a file without its extension, or get just a file's extension? What are some good ways to do basename and dirname?

michaelk · 11-07-2022, 01:21 PM

I don't know if better but there are many ways.

Assuming all filenames have a _ ...

Code:

basename ${X#*_} .mp3

or

echo "$X" | awk -F"[_|.]" '{print $2}'

GPGAgent · 11-07-2022, 04:50 PM

Quote:

Originally Posted by boughtonp

There's no need for the :99 part, and equivalent to basename can be achieved in Bash itself.

See BashFAQ #73: How can I use parameter expansion? How can I get substrings? How can I get a file without its extension, or get just a file's extension? What are some good ways to do basename and dirname?

#73 is just what I wanted - thanks

MadeInGermany · 11-08-2022, 03:37 AM

Code:

X="0001_ThisBook.mp3"
# delete pattern from the right
bn=${X%.*}
# delete pattern from the left
echo "${bn#*_}"

grail · 11-08-2022, 07:54 AM

You can also use a regex:

Code:

X="0001_ThisBook.mp3"
reg='_([^.]+)'

[[ "$X" =~ $reg ]] && echo "${BASH_REMATCH[1]}"