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Old 10-31-2011, 11:49 AM   #1
Pinglu
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Registered: Sep 2011
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Regular Expression in IF statement not working in ksh


Hi,

Here is my code,

if [[ "GEORGE T MAY ESTATE OF " = @(ESTATE OF|SUCCESSION DE) ]] ; then
input=`echo "GEORGE ESTATE OF T MAY" | sed -e 's/ESTATE OF//'`
fi



I want to find the pattern which is "ESTATE OF" or "SUCCESSION DE". In the testing code above, I want to go into that if statement, but as the result, it doesn't execute the if statement. I'm wondering how I can let the if statement be true.

Thanks
 
Old 10-31-2011, 01:03 PM   #2
grail
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How do you know you do not go into the if? There is no output from your example.
 
Old 11-01-2011, 09:56 AM   #3
David the H.
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Please use [code][/code] tags around your code, to preserve formatting and to improve readability.

Your string values are confusing to me. Please explain exactly what you are doing, and give us some examples of the input, the desired output, and the actual output you get, if any.


At first glance, assuming ksh's [[ test and extended globs are the same as in bash, then you can't match substrings this way. "=" only matches whole strings, so you have to formulate the glob to account for that, or else use a "=~" regex match.

Also, depending on your exact goals, it might be possible to simply replace the test with a parameter substitution.

Code:
$ sub="ESTATE OF |SUCCESSION DE "

$ input="GEORGE ESTATE OF T MAY"
$ echo "${input/@($sub)}"
GEORGE T MAY

$ input="GEORGE SUCCESSION DE T MAY"
$ echo "${input/@($sub)}"
GEORGE T MAY
Finally, $(..) is highly recommended over `..`. (The link is for bash, but it's equally true for ksh.)
 
  


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