[SOLVED] Insert heading in awk

vanish78 · 06-08-2011, 03:55 AM

Hi,

I need to put headings ontop of the output of this awk script :

#!/bin/sh

PHP Code:



date 
df=`df -Pl | grep "^/dev" | awk '{print $6, int($2/1024+0.5) , int($4/1024+0.5) }' | sed "s/%//"` 
echo "$df" 
 
 
/ 69550 55518 
/tmp 7933 7375 
/u01 49596 23227 
/vote1 1024 742 
/vote2 1024 742 
/vote3 1024 742 
/ocr 1024 506 
/ocrmir 1024 506 
/backup 204797 166291

but this script errors out :

PHP Code:



#!/bin/sh 
date 
df=`df -Pl | grep "^/dev" | awk 'BEGIN {print "MP TOTAL USED" 
                                        print "-- ----- ----"} 
'{print $6, int($2/1024+0.5) , int($4/1024+0.5) }' | sed "s/%//"` 
echo "$df" 
 
 
Wed Jun  8 10:54:38 SAST 2011 
-bash: command substitution: line 7: syntax error near unexpected token `(' 
-bash: command substitution: line 7: `'{print $6, int($2/1024+0.5) , int($4/1024+0.5) }' | sed "s/%//"'

Please help, thanks

divyashree · 06-08-2011, 04:19 AM

Quote:

#!/bin/sh
df=`df -Pl | grep "^/dev" | awk 'BEGIN {print "MP TOTAL USED"
print "-- ----- ----"}
'{print $6, int($2/1024+0.5) , int($4/1024+0.5) }' | sed "s/%//"`
echo "$df"

The wrong is marked as red .. its the extra char you have. Remove that single quote.

grail · 06-08-2011, 08:19 AM

Probably a silly question, but is there a reason to put it all in a variable just to echo it all out again?

Also, df has the -h option to make human readable which nullifies the need for all the math.

So you could have just done:

Code:

df -Plh | awk 'BEGIN{print strftime();print "MP TOTAL USED\n-- ----- ----"}/^\/dev/{print $6,$2,$4}'

I would also probably prefer to use printf to get the spacing nicer too.

oh ... and I had no idea why the sed is even there??