[SOLVED] how do i sequentially run multiple awk/bash scripts

atjurhs · 02-01-2023, 12:02 PM

hi guys,

i have several bash scripts that each call awk.

from the command line, instead of doing

./script1.awk
./script2.awk
./script3.awk

i would like to do something like

./(script1.awk script2.awk script3.awk)

that of course doesn't work, but how can i do this?

computersavvy · 02-01-2023, 12:14 PM

One easy way would be to chain the commands like

Code:

./script1.awk ; ./script2.awk ; ./script3.awk

or 

./script1.awk && ./script2.awk && ./script3.awk

That could be done even easier if you wrote another script to call each of those one after the other.
I would also suggest that you add the full path to each script and possibly even some cd steps in there so you ensure the scripts are being performed in the proper location.

atjurhs · 02-01-2023, 12:16 PM

yep, i think i figured it out as you were typing

sorry to waste your digits

jayjwa · 02-01-2023, 12:18 PM

for loops. Bash/Zsh, possibly others:

Code:

for scripts in $( seq 1 3 ); do
  ./script${scripts}.sh
done

khbkhb · 02-01-2023, 03:31 PM

you might want to think about stopping the sequence if any of them fail. See the FM about && operator.
Or more wordy, but allowing for greater flexibility the if ! $script ; then ; fi construct.

MadeInGermany · 02-02-2023, 04:26 AM

That is what the

Code:

./script1.awk && ./script2.awk && ./script3.awk

does.
In contrast to a semicolon the && only continues if the exit status is good.
In a loop you would use a break statement:

Code:

for scripts in 1 2 3; do
  ./script${scripts}.sh || break
done

The || runs the following statement if the exit status is bad.