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#for i in *\(*\)*; do j=`echo $i |sed -e 's/[()]//g'`; mv "$i" "$j"; done
for f in *; do fn=`echo $f|sed 's/\([[:alnum:]]*\)[[:space:]]*(.)\(\..*\)/\1\2/'`; mv $f $fn; done
The first one only removes parentheses, so I don't want that one. I tried the second one but it just won't work; it does nothing. I don't really understand whats wrong.
(1) Set the input field separator temporarily to nothing (to get around white space wrongly delimiting the filenames.)
(2) Put the rename command in a find command, to enact the command on the entire current directory tree.
(3) The regular expression 's/ ?\(.*\)\ ?//' replaces matches of (0-1 spaces)(anything in parentheses)(0-1 spaces) with the empty string.
HTH
Last edited by jhwilliams; 12-24-2011 at 12:11 PM.
Well, that's not actually Perl, just a call to a remote Perl script. It's all bash. But yes, if you wanted to script it you could:
Code:
#!/bin/bash
# First command, get rid of all of the () stuff:
IFS='' find -type f -exec rename 's/ ?\(.*\)\ ?//' {} \;
# Okay, now remove the first 3 chars (or replace with 3 with however many you want.)
IFS='' find -type f -exec rename 's/^.{3}//' {} \;
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