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I have written the following function and want to set a default if user does not supply a value to the option "-t". Haw can I handle this?
Code:
myfunc ()
{
local nt ng
local OPTIND OPTARG
local shortopts=":t::g:"
while getopts "$shortopts" arg; do
case $arg in
("t") nt=${OPTARG} ;;
("g") ng=${OPTARG} ;;
(*)
printf "getopts: Error Reporting Mode | Silent "
printf "arg: $arg"
case $arg in
(":")
printf " No value provided to -${OPTARG} option."
printf " Give a value, e.g. \"-${OPTARG} 3\"."
break
;;
("?")
printf "User option not dufined in shortopts."
printf "Invalid -${OPTARG} option provided."
break
;;
esac
break
;;
esac
done
printf '%s\n' "nt: $nt | ng: $ng"
}
Would the default value have to be set after the "while getopts" construct?
default should be set before the loop
Quote:
Originally Posted by Faki
What happens with "nt=${OPTARG}" if there in no "arg"?
getopts will set OPTARG if : was specified (or will report an error if that argument was missing). But you can check it yourself. Or see (for example) here: https://www.golinuxcloud.com/bash-getopts/
I am still quite unsure about this. I want the default to be nt=0 if the "-t" option is not specified. If it is specified only with "-t" I want to have "nt=1", or use the user defined one if supplied with (e.g. "-t3").
Does getopts support double colon "::" though? I think there is some program that accepts "::" for optional values but cannot remember if it is "getopts" or not.
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