function showing a list of variable and value: (dynamic variable name)

budhax · 09-19-2008, 05:44 PM

Hello,
I would like to build a function showing a list of variables like:
variable name : [variable value]
but, respectfully, Mr BASH cannot understand this: ${$name}

Is there a way to do that (using a FOR loop and a list VAR=CN1 ...)?
Thanks

Here my code:

Code:

#^!/bin/bash

fARP=fARP
fCAP=fCAP
fIVS=fIVS
fPSK=fPSK
fXOR=fXOR
#
CN1=eth1
VC1=rtap0
CN2=rausb0
VC2=wifi0
#
RTE=200
MEID=IPW22
DICO=Dic.LOG
IP0=192.168.1.100
IP1=192.168.1.101
MAC=50:41:32:23:14:05
#
VAR="CN1 VC1 CN2 VC2 RTE MEID DICO MAC"

function ShowVAR () {
	echo var_name : [var_value]
	for name in $VAR; do
		value=${$name}
		echo  "$name : $value"
	done
}

budhax · 09-19-2008, 07:05 PM

I found a solution (googleling with: bash dynamic variable name).

Code:

function ShowVAR () {
	echo var_name : [var_value]
	for name in $VAR; do
		#value=${$name}
		echo  "$name : ${!name}"
	done
}

Thanks and regards.

Source:
http://www.commentcamarche.net/forum...bleme-variable