Dear all,


I am successfully execute the below command in my script :

sed '/findstring/s//replacestring/g' find1.txt > /root/Desktop/output1.txt

but when I want to replace it with some runtime input it fails .
I want to accept a string from user and then find, replace it.
Below is my script :

#/bin/bash
#Script for Find and Replace

#filename=$1

findstring=$1

replacestring=$2

echo $findstring
echo $replacestring

#sed '/$findstring/s//$replacestring/g' find1.txt > /root/Desktop/output1.txt



# Below line executed successfully.

#sed '/tea/s//milk/g' find1.txt > /root/Desktop/output1.txt


#sed -i 's/findstring/replacestring/g' *

echo "Script executed successfully"



Pls help how could I achieve this.


Thanks & Regards

Adarsh Sharma

To make the shell handle your variables you need to use " instead of '

i.e.

sed "/$findstring/s//$replacestring/g" find1.txt > /root/Desktop/output1.txt

Your syntax looks a bit strange to me. I'm used to writing it a bit differently:

sed "s/$findstring/$replacestring/g"

1 members found this post helpful.

Thanks a lot ! It works.


Best Regards

Adarsh Sharma

Please mark as SOLVED once you have a working solution.