File count with script?

fbfd1338 · 10-22-2005, 12:23 AM

I am trying to write a small script that will rename my digital camera photo's the have weird names like DCD 20040925 to a simpler naming of just a 4 digit numbering system ie. 0001, 0002, 0003.jpg, etc. I was suggested to me that I do a file count of the folder that the pics are in, then have the names changed to progress up to the file count? Wel I am having trouble finding how to obtain a file count, and curious if there may be a better way to do this? Thanks a bunch.

-Kevin

Dark_Helmet · 10-22-2005, 12:53 AM

One possible way is to run the following command:

Code:

ls -1 | wc -l

Just to be thorough, that's a one (1) for the option to ls.

That will count how many things are in a directory. "Things" includes regular files and directories. If there are directories mixed with the images, I would suggest reading up on the find command (man find) with specific attention to the "-type" and "-maxdepth" options.

eddiebaby1023 · 10-22-2005, 08:55 AM

Quote:

Originally posted by Dark_Helmet
One possible way is to run the following command:

Code:

ls -1 | wc -l

Just to be thorough, that's a one (1) for the option to ls.

That will count how many things are in a directory. "Things" includes regular files and directories. If there are directories mixed with the images, I would suggest reading up on the find command (man find) with specific attention to the "-type" and "-maxdepth" options.

ls will automatically infer -1(one) if its output isn't routed to a terminal, so ls | wc -l is equivalent (and shorter). Try:

Code:

ls 
ls | cat

to see the difference.

homey · 10-22-2005, 09:24 AM

Here is something which may get you started. You should try it on a practice folder first.

Code:

#!/bin/bash
#Example: ./test /home/images
usage()
{
   echo "Usage: $0 Directory_Name"
   echo "Example: ./test /home/images"
   exit 1;
}

test -d "$1" || usage

dir="$1"

mkdir $dir/tmp 2> /dev/null

ls $dir | \
while read i ; do
   n=$(( $n + 1 ))
   j=`echo "$i" | awk -F. '{print $2}'`
   mv -v "$dir/$i" "/tmp/file$n.$j"
if [ $n -lt '10' ]; then
   mv "/tmp/file$n.$j" "/tmp/file00$n.$j"
elif [ $n -ge '10' -a $n -lt '100' ]; then
   mv "/tmp/file$n.$j" "/tmp/file0$n.$j"
fi
done
find /tmp -type f -name 'file*' -exec mv -v {} $dir \;

fbfd1338 · 10-23-2005, 03:02 AM

Homey.....
Thank you for the help, with a few minor alterations to the script I was able to use alot of what you gave me and it works perfect.