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Old 05-27-2003, 05:34 PM   #1
Sammy2ooo
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Registered: Jan 2003
Location: nearby switzerland
Distribution: Suse 8.0 / Suse 9.0 / Slackware 9.1 / Debian Sarge testing / Gentoo 1.4.10
Posts: 165

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cut / awk command??


Hi everybody

i got a question regarding line based searching
if i have file which looks for example like this:

Quote:
Host: 192.168.100.2 () bla 123
Host: 192.168.100.3 () bla 123
Host: 192.168.100.4 () bla 123
Host: 192.168.100.5 () bla 123
Host: 192.168.100.6 () bla 123
how am i able to extract only the ips??
afterwards it should look like this:

Quote:
192.168.100.2
192.168.100.3
192.168.100.4
192.168.100.5
192.168.100.6
cat file | grep Host: doesn't work and couldn't find any option to extract the ips

i heard of a awk command but don't know how the heck to use it to realize this

Any help or hint would be apreciated


Friendly Regards

Sam
 
Old 05-27-2003, 05:46 PM   #2
awdoyle
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Registered: Aug 2002
Location: Portland, OR
Distribution: Xubuntu
Posts: 135

Rep: Reputation: 15
$ awk '{print $2}' filename

Andrew
 
  


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