[SOLVED] Command to grep complete line

Fracker · 05-11-2011, 02:47 AM

cat filename| awk '{print $3}' | cut -c -3 | cut -c 2- | grep 66

this returns the lines containing "66" at 2nd 2 characters of 3rd column of a line, now i need complete lines for this, how can i do it?

brownie_cookie · 05-11-2011, 02:53 AM

so if i get this right... you search for line with 66 in it (at the 2nd character of the 3rd column), and when you found that, you want to show the entire line of your result?

for example

Code:

abc def g66 blablabla1
abc def g66 blablabla2
abc def g66 blablabla3
abc def g67 blablabla

you need to get as result

Code:

abc def g66 blablabla1
abc def g66 blablabla2
abc def g66 blablabla3

???

Fracker · 05-11-2011, 03:00 AM

yes just with tiny difference

From

Code:

abc def g663123123 blablabla1
abc def g66921321 blablabla2
abc def g6631231 blablabla3
abc def g673123123 blablabla

this

Code:

abc def g663123123 blablabla1
abc def g66921321 blablabla2
abc def g6631231 blablabla3

brownie_cookie · 05-11-2011, 03:09 AM

and if you do

Code:

cat file | grep 66

but is it possible that there are also '66' in the first column or seconde column, or??

Fracker · 05-11-2011, 04:29 AM

Quote:

Originally Posted by brownie_cookie

and if you do

Code:

cat file | grep 66

but is it possible that there are also '66' in the first column or seconde column, or??

Yes there is possibility, even it could be more 66 at column 3 which is why i use the above command which initially get 3rd column then get 1st 3 character and then remove 1 character..

grail · 05-11-2011, 04:48 AM

awk does not need the rest of that guff:

Code:

awk '$3 ~ /^.66/' file

This will now work even if you have:

Quote:

abc def g67316623123 blablabla

This will not be displayed, unlike with the grep.

Fracker · 05-11-2011, 04:52 AM

Thanks, this works like a charm