combine output with xargs

karthik4455 · 03-18-2016, 12:18 AM

[root@karthik-linv ~]# which ethtool
/sbin/ethtool

What I'm trying to achieve is how can I run "/sbin/ethtool eth0" from a single command. This is important because I've to run this from a script. Since some of the unix machines have ethtool under "/usr/sbin/" I need to find the directory and execute it from there.

I'm trying this but it's not working as eth0 is added before to /sbin/ethtool instead of after.
[root@karthik-linv ~]# which ethtool | xargs -l eth0
xargs: eth0: No Such file or directory

Best Regards,
Karthik

timl · 03-18-2016, 12:36 AM

First of all, get out of root and login as a normal user

Maybe I am missing what the problem is here. Can't you just say

Quote:

ethtool eth0

karthik4455 · 03-18-2016, 12:49 AM

Quote:

Originally Posted by timl

First of all, get out of root and login as a normal user

Maybe I am missing what the problem is here. Can't you just say

Hi Tim,

Actually I'm including this like below in my perl script:
(ethtool eth0 | grep Duplex)

However, when I execute my script I'm seeing below:
bash: line 10: ethtool: command not found

So to resolve this I have to provide the path as well like (/sbin/ethtool eth0 | grep Duplex). When I do this it's working. Only issue I foresee here is some of the linux systems have ethtool within /usr/sbin/ethtool. This is the reason I'm trying to find the path using which command and interpret the output.

grail · 03-18-2016, 01:36 AM

Why not assign the output to a variable and use as a command:

Code:

ett=$(which ethtool)

$ett eth0

pan64 · 03-18-2016, 04:55 AM

in perl you can easily check if /sbin/ethtool and/or /usr/bin/ethtool exists. And use that.