[SOLVED] cat command for yesterday entries

mahan77 · 04-26-2013, 03:47 PM

I like to get yesterday entries from log file so that I can send that to my email every day.
This command will provide today’s from log file

cat /var/log/fail2ban.log | grep `date +%Y\-%m\-%d`

how do i rewrite this command for yesterday entries?

cortman · 04-26-2013, 04:04 PM

I found this with Google.

mahan77 · 04-26-2013, 04:10 PM

Quote:

Originally Posted by cortman

I found this with Google.

This command don't work

Habitual · 04-26-2013, 04:12 PM

Code:

grep $(date +"%Y-%m-%d" --date="1 days ago")  /var/log/fail2ban.log

mahan77 · 04-26-2013, 04:14 PM

Quote:

Originally Posted by Habitual

Code:

grep $(date +"%Y-%m-%d" --date="1 days ago") /var/log/messages

Thank you so much

Habitual · 04-26-2013, 04:17 PM

Sure!

and it's

Code:

grep $(date +"%Y-%m-%d" --date="1 days ago")  /var/log/fail2ban.log

in case email sent you my first reply.

mahan77 · 04-26-2013, 04:24 PM

Quote:

Originally Posted by Habitual

Sure!

and it's

Code:

grep $(date +"%Y-%m-%d" --date="1 days ago")  /var/log/fail2ban.log

in case email sent you my first reply.

keep up the good work
thanks again

David the H. · 04-29-2013, 09:43 AM

date +"%F" is the same as date +"%Y-%m-%d", btw.

I'm not familiar with the format of this log, but it appears that the date string we want to match is at the beginning of the line, so I suggest modifying it like this:

Code:

grep "$( date -d '-1 day' +'^%F' )"  /var/log/fail2ban.log

This would keep it from potentially matching any dates elsewhere in the text.

Habitual · 04-30-2013, 09:45 AM

Quote:

Originally Posted by David the H.

date +"%F" is the same as date +"%Y-%m-%d", btw

and a whole lot less typing, too. Thanks!