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Old 01-17-2008, 12:17 AM   #1
Ashok_mittal
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Registered: Dec 2007
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Cool awk command to find if any one argument is matching


What is the command to find out the lines having a certain word in it.
I have given a command :

awk '{if($1=="ashok")print}' awk.txt

here awk.txt is a file containing differnet lines.
how i amend this command to get every line printed having ashok in any column
like awk.txt file

line1--> ashok mehera 23

line2--> mittal ashok 25

line3--> anand goyal 34


so from the above command only will print line 1 instead i want that both line 1 and line 2 should be printed.
 
Old 01-17-2008, 12:19 AM   #2
druuna
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Hi,

awk '/ashok/ { print }' awk.txt should work.

All between / and / is what awk is lookin for in a line, if it finds a hit, the line is printed.

Hope this helps.
 
Old 01-17-2008, 12:38 AM   #3
Ashok_mittal
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Quote:
Originally Posted by druuna View Post
Hi,

awk '/ashok/ { print }' awk.txt should work.

All between / and / is what awk is lookin for in a line, if it finds a hit, the line is printed.

Hope this helps.

Thanks Buddy it works efficiently
 
  


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