I have a script that is used to start a application process.Argument "start" has to be passed to this script to start the process.

When I run the script there are two process created for the same :

root 22760 22682 3 13:32 pts/2 00:00:00 <scriptname> start
root 22850 22760 0 13:32 pts/2 00:00:00 <scriptname> start

Not able to understand why there are two processes .Also one of them is a child of another.
This is failing a check in the script which checks if there is already a running script (check number of process of the script >1)

Any ideas are welcome .

How are you checking if there is a running script?
Can you paste your code here?

How are you checking if there is a running script?

var3=`ps -ef|grep "<scriptname> start"|grep -v grep|awk '{print $2}'`
cnt=$(ps -ef | grep "<scriptname> start" | grep -vc grep)
if [[ "${cnt}" -ge 2 ]]
then
echo "The process is already running..... : $var3"
exit 1
fi

So the script is exiting as we can see two processes running when script is executed.

Are you using this segment of code in same script which is running twice?
If same script is running two or mor times and you use this code in another script and run it, it will show you the message that the script is already running.

When you are passing argument start, in that segment of code, make sure it should not same script another time.
If you kill one of the script, are both script killed? You can try this after clicking child process.

you can also try to use pgrep scriptname