How can I determine the path of a shell script that I'm running right now ?

basher400 · 10-25-2006, 07:37 AM

ok, I'm in:
/usr1/boor/home/

and I'm running:
/usr1/Asher/home/scripts/main.sh

I need for main.sh to know the path it is running in - no matter from where I'm running it.

the $0 is the closest I got so far, the only problem is $0 also contains the name of the file itself ("main.sh") and I only want the path ("/usr1/Asher/home/scripts/")

any ideas ?
oh and I would rather not use the "cd" command in the script because it is needed to be in the same place later in the script.
thanks

druuna · 10-25-2006, 07:52 AM

Hi,

It's not clear to me what you actually want to do, but the following hopefully helps:

dirname $0 => return the directory part.

battletroll · 10-25-2006, 07:54 AM

Quote:

Originally Posted by basher400

ok, I'm in:
/usr1/boor/home/

and I'm running:
/usr1/Asher/home/scripts/main.sh

I need for main.sh to know the path it is running in - no matter from where I'm running it.

the $0 is the closest I got so far, the only problem is $0 also contains the name of the file itself ("main.sh") and I only want the path ("/usr1/Asher/home/scripts/")

any ideas ?
oh and I would rather not use the "cd" command in the script because it is needed to be in the same place later in the script.
thanks

$PWD=`pwd`

SCerovec · 10-25-2006, 08:10 AM

did you read bash's man?
did you try
echo $_
?

basher400 · 10-25-2006, 08:22 AM

Quote:

Originally Posted by SCerovec

did you read bash's man?
did you try
echo $_
?

echo $_ didn't work

basher400 · 10-25-2006, 08:23 AM

Quote:

Originally Posted by battletroll

$PWD=`pwd`

this I tried.
it gives me the path of which i'm running script from (/usr1/boor/home/), not the path of main.sh

pwc101 · 10-25-2006, 08:25 AM

Quote:

Originally Posted by battletroll

$PWD=`pwd`

$PWD is a system variable on my machine, so there's no need to define it. Just calling $PWD in the script will return the path.

basher400 · 10-25-2006, 08:31 AM

Quote:

Originally Posted by druuna

Hi,

It's not clear to me what you actually want to do, but the following hopefully helps:

dirname $0 => return the directory part.

thanks

this works:

Code:

$(dirname $0)