Command line question

satimis · 06-12-2005, 09:43 PM

Hi folks,

What single command line shall be used to replace 3 separate commands such as;

# lsmod | grep filaA
# lsmod | grep filaB
# lsmod | grep filaB

TIA

B.R.
satimis

freegazer · 06-12-2005, 09:54 PM

concatenate them using && or ; to run each command sequentially.
the first option may (depending on the context you are using) stop at the first command that returns an erro the second will just keep rolling

satimis · 06-12-2005, 10:08 PM

Hi freegazer,

Tks for your advice. Test performed as follows;

# lsmod | grep mpu401; grep olp3; grep uart401

Code:

snd_mpu401_uart        10049  1 snd_via82xx
snd_rawmidi            28641  2 snd_seq_virmidi,snd_mpu401_uart
snd                    56741  18 snd_virmidi,snd_seq_virmidi,snd_seq_oss,snd_seq,snd_via82xx,snd_ac97_codec,snd_pcm_oss,snd_mixer_oss,snd_pcm,snd_timer,snd_mpu401_uart,snd_rawmidi,snd_seq_device

# lsmod | grep mpu401 && grep olp3 && grep uart401

Code:

snd_mpu401_uart        10049  1 snd_via82xx
snd_rawmidi            28641  2 snd_seq_virmidi,snd_mpu401_uart
snd                    56741  18 snd_virmidi,snd_seq_virmidi,snd_seq_oss,snd_seq,snd_via82xx,snd_ac97_codec,snd_pcm_oss,snd_mixer_oss,snd_pcm,snd_timer,snd_mpu401_uart,snd_rawmidi,snd_seq_device

Both hung at the end until I issued
[Ctrl]+ c
to stop them.

It is possible avoiding repeating 'grep'?

TIA

B.R.
satimis

Berhanie · 06-12-2005, 10:24 PM

Code:

lsmod | grep -E 'fileA|fileB|fileC'

(the '|' in the grep command is an or, not a pipe).

satimis · 06-12-2005, 10:36 PM

Hi Berhanie,

Tks for your advice.

Quote:

Code:

lsmod | grep -E 'fileA|fileB|fileC'

(the '|' in the grep command is an or, not a pipe).

It worked but all contents were mixed. Would it be possible to separte the contents indicating their owner?

TIA

B.R.
satimis

Berhanie · 06-12-2005, 10:49 PM

To elaborate on freegazer's suggestion, if you want everything performed sequentially, run somthing like

Code:

lsmod | grep fileA ; lsmod | grep fileB; lsmod | grep fileB

satimis · 06-12-2005, 10:55 PM

Hi Berhanie,

Tks for your advice.

I'm trying to discover whether it would be possible avoiding repeat-typing 'grep' and 'lsmod'

Your suggestion worked for me but how to separate the printout indicating their ownership

TIA

B.R.
satimis

Berhanie · 06-13-2005, 09:32 AM

Quote:

Originally posted by satimis
but how to separate the printout indicating their ownership

Please explain what you mean. I don't understand what you're trying to do.

satimis · 06-13-2005, 10:08 AM

Hi Berhanie,

# lsmod | grep -E fileA
# lsmod | grep -E fileB
# lsmod | grep -E fileC
each will display one bundle of files

If
# lsmod | grep -E 'fileA|fileB|fileC'
all files will be mix-displayed. It will take time to sort out which of them belongs to fileA, fileB and fileC respectively.

B.R.
satimis

oneandoneis2 · 06-13-2005, 10:32 AM

What about:

Code:

for name in {filaA,filaB,filaC};do lsmod | grep $name; done

If you need them visisbly split, then you could use:

Code:

for name in {filaA,filaB,filaC};do lsmod | grep $name && echo "-----------"; done

Then you'll get a grep'd lsmod for filaA, followed by a line of dashes, followed by a grep'd filaB, etc

jschiwal · 06-13-2005, 11:21 AM

Another way of doing it is to use the '-e' grep option.

lsmod | grep -e pattern1 -e pattern2 -e pattern3

I will sometimes use this with "-v" option to eliminate lines from the locate command which can be very long, using the up arrow to repeat the last line and adding a couple patterns at a time until I eliminate enough results to find what I want.

satimis · 06-20-2005, 09:12 PM

Hi oneandoneis2,

Tks for your advice.

Quote:

Code:

for name in {filaA,filaB,filaC};do lsmod | grep $name; done

Code:

for name in {filaA,filaB,filaC};do lsmod | grep $name && echo "-----------"; done

Both work for me.

But if one of the files without printout then I have to guess.

B.R.
satimis

satimis · 06-20-2005, 09:28 PM

Hi jschiwal,

Tks for your advice.

Quote:

lsmod | grep -e pattern1 -e pattern2 -e pattern3

the command is short and easy to remember. However all printout are mixed. Besides it is not easy to find out which file has zero printout.

B.R.
satimis

frandalla · 06-20-2005, 09:37 PM

Quote:

Originally posted by satimis
Hi oneandoneis2,

Tks for your advice.

Both work for me.

But if one of the files without printout then I have to guess.

B.R.
satimis

so try it:
for name in {filaA,filaB,filaC};do lsmod | grep $name && echo "----- $name ------"; done

satimis · 06-20-2005, 09:46 PM

Hi frandalla,

Quote:

so try it:
for name in {filaA,filaB,filaC};do lsmod | grep $name && echo "----- $name ------"; done

Great. It works for me. Tks

B.R.
satimis