Bash for loop not working

cryptinitedemon · 04-21-2010, 03:26 PM

I have bash 4.0. I used the following for loop example, but all it outputs is "{1..10} instead of the actual numbers one through ten. why?

Code:

for a in {1..10}
do
  echo -n "$a "
done

pixellany · 04-21-2010, 03:33 PM

Code:

[mherring@mystical play]$ for a in $(seq 1 10); do echo $a; done
1
2
3
4
5
6
7
8
9
10

[mherring@mystical play]$ for a in {1..10}; do echo $a; done
1
2
3
4
5
6
7
8
9
10

cola · 04-24-2010, 08:45 AM

Quote:

Originally Posted by cryptinitedemon

I have bash 4.0. I used the following for loop example, but all it outputs is "{1..10} instead of the actual numbers one through ten. why?

Code:

for a in {1..10}
do
  echo -n "$a "
done

I don't see any problem with this.

pixellany · 04-24-2010, 08:49 AM

I actually made a script and cut and pasted your code into it. Works fine.

MTK358 · 04-24-2010, 10:14 AM

Quote:

Originally Posted by cryptinitedemon

I have bash 4.0. I used the following for loop example, but all it outputs is "{1..10} instead of the actual numbers one through ten. why?

Code:

for a in {1..10}
do
  echo -n "$a "
done

I copy/pasted that right into my terminal and it printed out:

Code:

1 2 3 4 5 6 7 8 9 10

colucix · 04-24-2010, 10:44 AM

First I'd check if braceexpand option is disabled for some reason:

Code:

set -o | grep braceexpand

it should be on by default.