[SOLVED] how to set a bit in register in linux flat form..

hai to all...

can any body tell me how to acess a bit of 8 bit register in linux flatform..

as in controller point of view we have sbit to set abit of register..but how can i set bit in case of linux..

for example:
unsigned char INTERRUPT;
now i have to set diffetrnt flags to each bit of INTERRUPT..



please help mee.
thanks in advance.....

set_bit : set a bit at the position.
clear_bit: clear a bit at the position.

I guess you are talking about the control/status/data registers in devices, rather than the CPU registers, which you need assembly language to access.

to set the n-th bit of x:
x |= 1<<n;
to clear the n-th bit of x:
x &= ~(1<<n);
to toggle the n-th bit of x:
x ^= 1<<n;

If you want to write all bits, just write a number to the register. For example, to accknowledge interrupts, write 0xFF to interrupt register.

Where is the register which you want to modify? If it is a CPU register, it may not be possible, or meaningful, except from kernel space. If it is a register in a memory-mapped or IO-mapped (x86) peripheral, then you can use the /dev/mem or /dev/port facilities. It may also be on something like a PCI or similar bus, in which case there are probably kernel facilities available to access the register.
The boolean logic to access a particular bit has been demonstrated by earlier posters.

--- rod.