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Old 11-03-2008, 12:35 PM   #1
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find command: trying to specify number of results to display

so im fiddling around with commands trying to learn scripts and i am trying to find the oldest file on the system.

I did 'find -iname / "*.*" -atime +300 -exec ls -lart -1 {} \;

and it seems to work fine but prints out several files and I only want the top most one -- the largest.

Is there a way to output only the first displayed result of this command or any other commands such as ls and stuff?

Last edited by dave247; 11-03-2008 at 01:28 PM.
Old 11-03-2008, 04:23 PM   #2
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cut and sed can both be used to select which lines to print/display. I think "head" also.

What texts are you using? You may want to go to and get the Bash Guide for Beginners.
Old 11-03-2008, 04:36 PM   #3
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head's what you want. man head for the syntax.


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