get julian date for a specific date

schneidz · 03-30-2011, 07:46 AM

hi, i run this command to get todays date in julian form:

Code:

date +%j
089

how would i get that format for e.g.- 12.25.2010 ?

i found this:

Code:

date -d '2007-04-01' +'%Y %j'

but it seems to be linux only

thankx,

David the H. · 03-30-2011, 11:12 AM

To be accurate, it's not a "Linux" thing, it's an option offered by the gnu version of date (gnu's tools generally have more options than their various unix counterparts). It is possible to install the gnu tools on other systems, if you're so inclined.

Otherwise I suggest you keep searching the web. I'm sure that there are at least partial solutions for what you want. Perhaps a similar feature can be found in perl or some other language?

schneidz · 03-30-2011, 03:33 PM

^ yeah, it seems like programming is involved which would be overkill for my needs.

i was hoping for some simple flag to the date command but i guess no joy.

trbennett48 · 04-04-2011, 04:34 PM

You could always use perl...
Here's a starting point for you:

Code:

#!/usr/bin/perl

use Time::Local 'timelocal_nocheck';

if ( $#ARGV+1 != 1 )
{
    printf("Usage: %s yyyy-mm-dd\n");
    exit(1);
}

$input_date = $ARGV[0];

if ( length($input_date) != 10 )
{
    printf("Format Error: Must be yyyy-mm-dd\n");
    exit 1;
}

($i_year, $i_mon, $i_day) = split "-", $input_date, 3;

printf("%s\n", 
   scalar ((localtime timelocal_nocheck 0,0,0,$i_day, $i_mon-1, $i_year - 1900)[7]));

-tony

schneidz · 04-05-2011, 08:29 AM

^ thanks, i was hoping not having to need to program something but i guess like a lot of other things in aix the linux equivalent has many more options.