Hello BSD users!

nautilus_1987 · 03-20-2004, 07:37 AM

I want to install OpenBSD. Here is my partition table:

Quote:

># fdisk -l

Disk /dev/hda: 255 heads, 63 sectors, 2434 cylinders
Units = cylinders of 16065 * 512 bytes

Device ----- Boot ----- Start ----- End ----- Blocks ----- Id ----- System
/dev/hda1 ----- 1 ----- 541 ----- 4345551 ----- 83 ----- Linux
/dev/hda2 ----- 542 ----- 929 ----- 3116610 ----- 83 ----- Linux
/dev/hda3 ----- * 930 ----- 1184 ----- 2048287+ ----- 7 ----- HPFS/NTFS (here I would like to install OpenBSD)
/dev/hda4 ----- 1185 ----- 2434 ----- 10040625 ----- f ----- Win95 Ext'd (LBA)
/dev/hda5 ----- 1185 ----- 1217 ----- 265041----- 82 ----- Linux swap
/dev/hda6 ----- 1218 ----- 2434 ----- 9775521 ----- b ----- Win95 FAT32

I want my OpenBSD to be located 930-1185 cyl., in other words I would like install BSD on third
primary partition of my 20GB Seagate drive - where WinXP now lives. I would like to know whether I can do it or not? cause "Install manual" says:

Quote:

Partition size and location limitations
Unfortunately, the full ability of the OS isn't available until AFTER the OS has been loaded into memory, and the booting process introduces limits of its own. The boot process has to utilize (and is thus limited by) the system's boot ROM. The OpenBSD i386 first-stage boot loader (biosboot(8)) also has its own internal 8G limitation, from an older BIOS limit.

For this reason, the entire /bsd file (the kernel) must be located on the disk within the boot ROM addressable area, or within the first 8G of the disk, whichever is smaller. This means that on some older i386 systems, the root partition must be completely within the first 504M, but for most newer computers, the root partition may be anywhere within the first 8G.

Do I violate this rule(sincerely saying I am not 100% assured)

???

Thank you!

chort · 03-20-2004, 03:29 PM

Well it looks like that's roughly in the middle of the 20GB disk, so yes that would certainly be over the 8GB limit.