[SOLVED] sed terminated prematurely by presence of \c in input
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sed terminated prematurely by presence of \c in input
Sed seems to react to the presence of "\" in its input if the immediately following character makes the pair a recognizable code. In the code following see that the "\a" and "\b" are missing in the output, and that the "\c" caused sed to terminate at that point. Is there any way to prevent it reacting like this?
Code:
g y="the shell built-in command. The following character sequences
> have special meaning:
> \a Alert (bell).
> \b Backspace.
>
> \c Suppress trailing newline.
> \f Form feed.
> \n Newline.
> \r Carriage return.
>
> \t Horizontal tab.
> \v Vertical tab.
>
> \\
> Literal backslash.
> \nnn
> The octal character whose ASCII code is nnn.
> Options"
g z="the"
g x="Options"
g w=$(echo -e "$y"|sed -n -e "/$z/,/$x/ p")
g echo "$w"
the shell built-in command. The following character sequences
have special meaning:
Alert (bell).
Backspace.
g
Same commands ready for pasting.
Code:
y="the shell built-in command. The following character sequences
have special meaning:
\a Alert (bell).
\b Backspace.
\c Suppress trailing newline.
\f Form feed.
\n Newline.
\r Carriage return.
\t Horizontal tab.
\v Vertical tab.
\\
Literal backslash.
\nnn
The octal character whose ASCII code is nnn.
Options"
z="the"
x="Options"
w=$(echo -e "$y"|sed -n -e "/$z/,/$x/ p")
echo "$w"
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