bash equivalent of <perl -e 'print time'>
Hi, I am trying to find the bash equivalent of <perl -e 'print time'> which prints the number of seconds since the epoch (January 1st 1970).
I have tried google, and also man time, man clock and man times. If I have missed something obvious please let me know.
This is for a personal project, not homework, and there is no real rush.
Thanks.
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