how to suppress some of ls's output?

BrianK · 03-03-2006, 02:50 PM

if you do:

ls /usr /opt

it will display the output of each /usr and /opt, but it precedes each with "/usr:" and "/opt:"
Those entries foul up scripts that use something like "foreach f (`ls /usr /opt`)"

Is there a way to suppress the output of "/usr:" and "/opt:"?

Thanks

gilead · 03-03-2006, 03:05 PM

I couldn't find anything in the ls man page to do this. Do either of the following help?

Code:

ls /opt /usr | sed -e '/:/d' -e '/^$/d'
find /opt /usr -maxdepth 1 -print

BrianK · 03-03-2006, 03:16 PM

Quote:

Originally Posted by gilead

I couldn't find anything in the ls man page to do this. Do either of the following help?

Code:

ls /opt /usr | sed -e '/:/d' -e '/^$/d'
find /opt /usr -maxdepth 1 -print

I didn't find anything in the man pages either. The first method is a bit cumbersome, but the latter method works good - I hadn't thought of using find.

still if there's a way to do it with just plain ol' ls, I'd be interested to know.