BASH: Listing contents of *.zip file into an array

cade · 05-18-2010, 06:31 PM

Hi, I am fairly new to programming and I need some help with my script.
I want to list the contents of a zip file amd put each entry into an array.
I've been doing

Code:

array=($(unzip*-qq*-l*"/path/to/file.zip"*|*awk*'{print*$4}'))

which works alright, and when I do

Code:

   for str in ${array[@]}; do
       echo "$str"
   done

It gives

Code:

   asdf/something
   base/asdf/something/the_quick_brown_fox_jumped_over_the_lazy_dog

.. until an item has a space in it's name

Code:

   for str in ${array[@]}; do
      echo "$str"
   done

Gives

Code:

   asdf/something
   base/asdf/something/the
   quick
   brown
   fox
   jumped
   over
   the
   lazy
   dog

Thanks

grail · 05-18-2010, 08:57 PM

Try a while/read loop instead:

Code:

while read line
do
<your stuff here>
done< <(<your unzip stuff here>)

Be aware of the space between the two signs <, after done

ta0kira · 05-18-2010, 09:06 PM

You need to use a different field separator ($IFS) that excludes spaces:

Code:

OLD_IFS="$IFS"
IFS=$'\n'
array=($(zip stuff...))
IFS="$OLD_IFS"

#...

for I in `seq 0 1 $((${#array[*]}-1))`; do
  #stuff with ${array[$I]}
done

Kevin Barry

ntubski · 05-18-2010, 09:35 PM

Code:

   for str in "${array[@]}"; do
      echo "$str"
   done

EDIT: this assumes array has been set correctly

ta0kira · 05-19-2010, 04:13 PM

Quote:

Originally Posted by ntubski

Code:

   for str in "${array[@]}"; do
      echo "$str"
   done

Thanks. I'm assuming this is just a correction to my loop and not to the IFS part.
Kevin Barry