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why is doesnt work? (awk, set)

set DBB = /goog/db/
ls -ltr db/ | awk '{print$DBB,$9}'

I want to add "/goog/db/" for each line with awk.

Since you are removing all of the items supplied by the -l option, why use it? You could use print just the filenames as is normal and add '/goog/db/' before each line.

My version of ls starts the filename at field 8:

Code:

ls -ltr | awk -v DBB=/goog/db/ 'NR>1 { printf DBB; for (i=8;i<NF;i++) printf "%s ", $i ; printf $NF"\n"}'

Because a filename may contain whitespace, some lines may contain more than 8 fields. You need to iterate from 8 to the end and print out each part.

Code:

find -printf "/goog/db %f\n"

Try it without spaces on both sides of the = sign.

End

Why it doesn't work:

Code:

set DBB = /goog/db/ ls -ltr db/ | awk '{print$DBB,$9}'

because you didn't put the bash variable (DDB) into awk correctly -- see jschiwal's syntax in post #2.
I assume (& applaud) that you are using the "DDB" variable to make your code more general. In general (:)), this is a good idea.
Why are you using ls's "-l" (ell) option when you are only going to throw everything from the 9th field on? The "-1" (one) option will put everything in a single column.
Why are you using awk when it will stumble over file names w/ spaces in them?
Try this instead:

Code:

DDB='/goog/db/' ls -1tr | while read F; do echo "$DDB$F"; done

Tested on my ~/.opera/sessions/ directory which has a file w/ spaces in its name.