LinuxQuestions.org - [SOLVED] Deleting a word in variable not knowing if it will be capitalized or not

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pedropt

10-24-2021 04:47 AM

Deleting a word in variable not knowing if it will be capitalized or not

in this text :

Quote:

I Think John went to the JOHN house

i can use :

Code:

var1="I Think John went to the house"

var2=$(echo "$var1" | sed 's/\<JOHN\>//g' | sed 's/\<John\>//g')

echo "$var2"

On this next code will fail because the Capitalized john is not in variable .

Code:

var1="I Think John is fine"

var2=$(echo "$var1" | sed 's/\<JOHN\>//g' | sed 's/\<John\>//g')

echo "$var2"

However if in next text the 2nd john does not show up then how can i write the code for the 2 options no matter if one of them does no show up in variable?

syg00

10-24-2021 05:39 AM

Depends on how specific the tests are - if only those 2, use alternation. If any variation of jOHn might arise, use a case-insensitive directive. See the doco from the GNU site or "info sed"; the manpage doesn't go this detail.

shruggy

10-24-2021 07:51 AM

There was a recent thread on case-insensitive matching in sed.

pedropt

10-25-2021 05:28 PM

Thanks

sundialsvcs

10-26-2021 01:21 PM

It's useful in general to read up on the topic of "regular expressions ('regexes')."

grail

10-27-2021 07:42 PM

Of course on something so trivial, you don't even need something like sed:

Code:

x='I Think John went to the JOHN house'

echo "${x//[Jj][Oo][Hh][Nn]/}"

I Think  went to the  house

MadeInGermany

10-30-2021 02:04 PM

And if you want to store it in a new variable, you can use a simple assignment

Code:

var1='I Think John went to the JOHN house'

var2=${var1//[Jj][Oo][Hh][Nn]/}

echo "$var2"

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