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Script: how to assign values to variables using "awk" results?

I want to write a script to find out the journal size of an ext3 file system. I have two commands (graciously provided by unSpawn):

Code:

The journal is located at inode: 

'tune2fs -l /dev/device | awk '/Journal inode/ {print $3}''



The size is:

debugfs -R "stat <inodenumber>" /dev/device 2>&1| awk '/Size: / {print $6}'|head -1

These commands work okay from the command line. I wanted to do something like

Code:

#!/bin/bash

#first parameter is the device name [s|h]dxy

 

inode='tune2fs -l /dev/device | awk '/Journal inode/ {print $3}''

#and noticed that that won't work.

# nor will

echo "Journal Size: "

debugfs -R "stat <inode>" /dev/$1 2>&1| awk '/Size: / {print $6}'|head -1 >1

Hm. So how can I get the value awk is printing in the first statement loaded into a variable (e.g. inode), and how would the second command print the journal size to the screen?

http://www.tldp.org/LDP/Bash-Beginne...e.html#chap_03 left me stumped...

Use backquotes(`) not single quotes(') to run a cmd and save the result thus:

var=`cmd`
echo $var

Aha. I'll try that this evening and be back with the result.

Anybody about why printing the results from within the script doesn't work? Can it be done less clumsily?

Yep, works. After some thought, I even remembered why :rolleyes:, thanks chrism01.

I solved the other question by the same method, i.e. put the statement in back ticks and assigned the value to a variable (yes, I know I could put them out with "echo" but later on I want to calculate the byte value into MBs, so...).