Script: how to assign values to variables using "awk" results?

JZL240I-U · 11-17-2008, 06:29 AM

I want to write a script to find out the journal size of an ext3 file system. I have two commands (graciously provided by unSpawn):

Code:

The journal is located at inode: 
'tune2fs -l /dev/device | awk '/Journal inode/ {print $3}''

The size is:
debugfs -R "stat <inodenumber>" /dev/device 2>&1| awk '/Size: / {print $6}'|head -1

These commands work okay from the command line. I wanted to do something like

Code:

#!/bin/bash
#first parameter is the device name [s|h]dxy
 
inode='tune2fs -l /dev/device | awk '/Journal inode/ {print $3}''
#and noticed that that won't work.
# nor will
echo "Journal Size: "
debugfs -R "stat <inode>" /dev/$1 2>&1| awk '/Size: / {print $6}'|head -1 >1

Hm. So how can I get the value awk is printing in the first statement loaded into a variable (e.g. inode), and how would the second command print the journal size to the screen?

http://www.tldp.org/LDP/Bash-Beginne...e.html#chap_03 left me stumped...

chrism01 · 11-17-2008, 06:34 AM

Use backquotes(`) not single quotes(') to run a cmd and save the result thus:

var=`cmd`
echo $var

JZL240I-U · 11-17-2008, 06:37 AM

Aha. I'll try that this evening and be back with the result.

Anybody about why printing the results from within the script doesn't work? Can it be done less clumsily?

JZL240I-U · 11-18-2008, 01:59 AM

Yep, works. After some thought, I even remembered why

, thanks chrism01.

I solved the other question by the same method, i.e. put the statement in back ticks and assigned the value to a variable (yes, I know I could put them out with "echo" but later on I want to calculate the byte value into MBs, so...).