LinuxQuestions.org - [SOLVED] Get number between / /

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Get number between / /

Hi,

i have:

avg = 97.384/97.799/98.561/0.539 ms

And I want to get the result

avg= 97.799 ms

I am confused how to do it directly so I am planning to erase the first number and slash so it will look like this

avg = 97.799/98.561/0.539 ms

by

Code:

sed 's@=.*/@ @g'

but it is giving strange output

avg 0.296 ms

Can anyone help me?

Thanks

sed 's/\//\n/g' | head -n 2 | tail -n 1

Quote:

Originally Posted by icygalz (Post 3878274)

Code:

sed 's@=.*/@ @g'

but it is giving strange output

avg 0.296 ms

Can anyone help me?

Thanks

Almost, slightly oversimplified. Not sure where the 0.296
might have come from, if I run your example it gives:

Code:

avg 0.539 ms

which is in line with your input.

Try

Code:

  echo "avg = 97.384/97.799/98.561/0.539 ms" |sed -r 's@ = [^/]+/([^/]+).*@= \1 ms@'

avg= 97.799 ms

Code:

avg=`echo 97.384/97.799/98.561/0.539 ms | awk -F / '{print $2}'`